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3x^2+10x+4=-x
We move all terms to the left:
3x^2+10x+4-(-x)=0
We add all the numbers together, and all the variables
3x^2+10x-(-1x)+4=0
We get rid of parentheses
3x^2+10x+1x+4=0
We add all the numbers together, and all the variables
3x^2+11x+4=0
a = 3; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·3·4
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{73}}{2*3}=\frac{-11-\sqrt{73}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{73}}{2*3}=\frac{-11+\sqrt{73}}{6} $
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